Mehmet Emre Tiryaki
Back to Notes

Probability Spaces

Probability Space

A probability space is a triple (Ω,B,P)(\Omega, \mathcal{B}, P) where Ω\Omega is the sample space, B\mathcal{B} is a σ\sigma-field of events, and P:B→[0,1]P : \mathcal{B} \to [0,1] is a probability measure satisfying

  1. P(A)≥0P(A) \ge 0 for all A∈BA \in \mathcal{B},
  2. for pairwise disjoint A1,A2,…∈BA_1, A_2, \ldots \in \mathcal{B}, P(⋃n=1∞An)=∑n=1∞P(An)P(\bigcup_{n=1}^{\infty} A_n) = \sum_{n=1}^{\infty} P(A_n),
  3. P(Ω)=1P(\Omega) = 1.

Properties

P(Ac)=1−P(A)P(A^c) = 1 - P(A), P(∅)=0P(\emptyset) = 0, and if A⊆BA \subseteq B then P(A)≤P(B)P(A) \le P(B).

Inclusion-exclusion,

P(⋃j=1nAj)=∑r=1n(−1)r+1∑1≤i1<⋯<ir≤nP(Ai1∩⋯∩Air)P\Big(\bigcup_{j=1}^{n} A_j\Big) = \sum_{r=1}^{n} (-1)^{r+1} \sum_{1 \le i_1 < \cdots < i_r \le n} P(A_{i_1} \cap \cdots \cap A_{i_r})

For any events,

P(⋃n=1∞An)≤∑n=1∞P(An)P\Big(\bigcup_{n=1}^{\infty} A_n\Big) \le \sum_{n=1}^{\infty} P(A_n)

Continuity: if An↑AA_n \uparrow A then P(An)↑P(A)=P(⋃nAn)P(A_n) \uparrow P(A) = P(\bigcup_n A_n), and if An↓AA_n \downarrow A then P(An)↓P(A)=P(⋂nAn)P(A_n) \downarrow P(A) = P(\bigcap_n A_n).

Fatou's lemma for sets,

P(lim inf⁡n→∞An)≤lim inf⁡n→∞P(An)≤lim sup⁡n→∞P(An)≤P(lim sup⁡n→∞An)P(\liminf_{n \to \infty} A_n) \le \liminf_{n \to \infty} P(A_n) \le \limsup_{n \to \infty} P(A_n) \le P(\limsup_{n \to \infty} A_n)

Distribution Function

For PP on (R,B(R))(\mathbb{R}, \mathcal{B}(\mathbb{R})) define F(x)=P((−∞,x])F(x) = P((-\infty, x]) for all xx. Then

  1. FF is right-continuous, F(x+)=lim⁡y↓xF(y)=F(x)F(x+) = \lim_{y \downarrow x} F(y) = F(x),
  2. FF is non-decreasing,
  3. lim⁡x→−∞F(x)=0\lim_{x \to -\infty} F(x) = 0 and lim⁡x→∞F(x)=1\lim_{x \to \infty} F(x) = 1.

A function F:R→[0,1]F : \mathbb{R} \to [0,1] satisfying the above is a distribution function (df).

Dynkin's π\pi-λ\lambda Theorem

Let P\mathcal{P} be a π\pi-system.

  1. If L\mathcal{L} is a λ\lambda-system and P⊆L\mathcal{P} \subseteq \mathcal{L}, then σ(P)⊆L\sigma(\mathcal{P}) \subseteq \mathcal{L}.
  2. σ(P)=L(P)\sigma(\mathcal{P}) = \mathcal{L}(\mathcal{P}), the smallest λ\lambda-system containing P\mathcal{P}.

A class that is both a π\pi-system and a λ\lambda-system is a σ\sigma-field.

Uniqueness

For probability measures P1,P2P_1, P_2 on (Ω,B)(\Omega, \mathcal{B}),

L={A∈B:P1(A)=P2(A)}\mathcal{L} = \{A \in \mathcal{B} : P_1(A) = P_2(A)\}

is a λ\lambda-system. So if P⊆B\mathcal{P} \subseteq \mathcal{B} is a π\pi-system and P1(A)=P2(A)P_1(A) = P_2(A) for all A∈PA \in \mathcal{P}, then P1(B)=P2(B)P_1(B) = P_2(B) for all B∈σ(P)B \in \sigma(\mathcal{P}).

In particular, if P1,P2P_1, P_2 have the same df, i.e. P1((−∞,x])=P2((−∞,x])P_1((-\infty, x]) = P_2((-\infty, x]) for all x∈Rx \in \mathbb{R}, then P1=P2P_1 = P_2 on B(R)\mathcal{B}(\mathbb{R}).

Constructions

Discrete Associate pip_i to ωi\omega_i such that pi≥0p_i \ge 0, ∑ipi=1\sum_i p_i = 1. Then P(A)=∑ωi∈ApiP(A) = \sum_{\omega_i \in A} p_i.

General Specify P(B)P(B) for BB in a class S\mathcal{S} of subsets of Ω\Omega, then extend PP to σ(S)\sigma(\mathcal{S}).

For G1⊆G2⊆2Ω\mathcal{G}_1 \subseteq \mathcal{G}_2 \subseteq 2^\Omega and Pi:Gi→[0,1]P_i : \mathcal{G}_i \to [0,1], P2P_2 is an extension of P1P_1 if P2(B)=P1(B)P_2(B) = P_1(B) for B∈G1B \in \mathcal{G}_1, equivalently P2∣G1=P1P_2|_{\mathcal{G}_1} = P_1.

PP is finitely additive on G\mathcal{G} if for pairwise disjoint A1,…,An∈GA_1, \ldots, A_n \in \mathcal{G} with ⋃i=1nAi∈G\bigcup_{i=1}^{n} A_i \in \mathcal{G},

P(⋃i=1nAi)=∑i=1nP(Ai)P\Big(\bigcup_{i=1}^{n} A_i\Big) = \sum_{i=1}^{n} P(A_i)

Half-open intervals in R\mathbb{R} and half-open rectangles in Rn\mathbb{R}^n form semialgebras. For a semialgebra S\mathcal{S},

A(S)={∑i∈ISi:I finite, {Si}i∈I disjoint, Si∈S}\mathcal{A}(\mathcal{S}) = \Big\{\sum_{i \in I} S_i : I \text{ finite},\ \{S_i\}_{i \in I} \text{ disjoint},\ S_i \in \mathcal{S}\Big\}

is the algebra generated by S\mathcal{S}, every set in it being a finite disjoint union of members of S\mathcal{S}.

First Extension Let S\mathcal{S} be a semialgebra and P:S→[0,1]P : \mathcal{S} \to [0,1] σ\sigma-additive with P(Ω)=1P(\Omega) = 1. Then PP has a unique σ\sigma-additive extension P~\tilde{P} to A(S)\mathcal{A}(\mathcal{S}). Specifically, if A=∑i∈IBiA = \sum_{i \in I} B_i with Bi∈SB_i \in \mathcal{S}, then P~(A)=∑i∈IP(Bi)\tilde{P}(A) = \sum_{i \in I} P(B_i).

Second Extension Let A\mathcal{A} be an algebra of subsets of Ω\Omega and P:A→[0,1]P : \mathcal{A} \to [0,1] σ\sigma-additive with P(Ω)=1P(\Omega) = 1. Then PP has a unique extension P~\tilde{P} to a probability measure on (Ω,σ(A))(\Omega, \sigma(\mathcal{A})).

Combining the two, a σ\sigma-additive P:S→[0,1]P : \mathcal{S} \to [0,1] on a semialgebra with P(Ω)=1P(\Omega) = 1 extends to a unique probability measure on (Ω,σ(S))(\Omega, \sigma(\mathcal{S})),

S→first extA(S)→second extσ(A(S))=σ(S)\mathcal{S} \xrightarrow{\text{first ext}} \mathcal{A}(\mathcal{S}) \xrightarrow{\text{second ext}} \sigma(\mathcal{A}(\mathcal{S})) = \sigma(\mathcal{S})

Lebesgue Measure on (0,1]

λ((a,b])=b−a\lambda((a,b]) = b - a on {(a,b]:0≤a≤b≤1}\{(a,b] : 0 \le a \le b \le 1\} is σ\sigma-additive, so it extends uniquely to B((0,1])\mathcal{B}((0,1]).

The σ\sigma-additivity uses compactness. K⊆RK \subseteq \mathbb{R} is compact if every open cover of KK has a finite subcover. Closed bounded intervals are compact.